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FB16344124: SwiftUI ".keyboardShortcut()" should be available on watchOS #600

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sindresorhus opened this issue Jan 17, 2025 · 0 comments
Open

FB16344124: SwiftUI ".keyboardShortcut()" should be available on watchOS #600

sindresorhus opened this issue Jan 17, 2025 · 0 comments

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@sindresorhus
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  • Date: 2025-01-18
  • Resolution: Open
  • Area: SwiftUI
  • OS: watchOS 11.2
  • Type: Suggestion

Description

When creating multi-platform apps, it requires too many #if-defs when your app uses a lot of keyboard shortcuts. .keyboardShortcut() should be available on watchOS, but just be documented to not do anything.
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@sindresorhus