call_method does not function correctly when a service has both UDP and TCP ports

[dayangshanbaoye]

If a service is provided on both UDP and TCP port, this info can not be handled correctly in self._offered_services. So I think we need to add a condition to make sure the provided service has the same protocol with the Client Service Instance, either TCP or UDP.

Before

# At this point the service should be found since an exception would have been raised before
        for s in self._offered_services:
            if s.service_id == self._service.id and s.instance_id == self._instance_id:
                dst_address = str(s.endpoint[0])
                dst_port = s.endpoint[1]
                break

After

for s in self._offered_services:
            if (
                s.service_id == self._service.id 
                and s.instance_id == self._instance_id 
                and s.protocol == self._protocol
            ):
                dst_address = str(s.endpoint[0])
                dst_port = s.endpoint[1]
                break

By the way, the snippets in the call_method, which specifies the UDP condition seems to be duplicated.

# In case of UDP, just send out the datagram and wait for the response
            # At this point the service should be found since an exception would have been raised before
            for s in self._offered_services:
                if (
                    s.service_id == self._service.id
                    and s.instance_id == self._instance_id
                ):
                    dst_address = str(s.endpoint[0])
                    dst_port = s.endpoint[1]
                    break

[dayangshanbaoye]

0: IPv4 Endpoint Option (172.16.64.64:53000 (UDP))
1: IPv4 Endpoint Option (172.16.64.64:53001 (TCP))